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4.9x^2+11x+0.4=0
a = 4.9; b = 11; c = +0.4;
Δ = b2-4ac
Δ = 112-4·4.9·0.4
Δ = 113.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{113.16}}{2*4.9}=\frac{-11-\sqrt{113.16}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{113.16}}{2*4.9}=\frac{-11+\sqrt{113.16}}{9.8} $
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